Original Meanwell LED driver HLG-320H-C700A 299.6W 435V 700mA 214~428V waterproof Mean well dimming Power Supply | Обустройство дома

Original Meanwell LED driver HLG-320H-C700A 299.6W 435V 700mA 214~428V waterproof Mean well dimming Power Supply | Обустройство дома

 Application 

HLG series Power Supply works outstandingly for all types of LED luminaire applications, such as LED street lighting, LED harbor lighting, LED bay lighting, LED flood lighting, LED fishing lamp, LED greenhouse lighting and so on.

Our Company 

We offer a vast of Power Supplies selection from the industry’s power supply leading manufacturer-Meanwell brand. It is our mission to provide a reliable solution to your power supply requirements. 

Since 2002, Kulon has been assisting the electronic industry’s engineers, buyers andtechnicians find ideal AC/DC, DC/DC, DC/AC Power Supply Solutions for their applications.

A.To increase the reliability of the S.P.S., we suggest users choose a unit that has a rating of 30% more power than actual need. 
For example, if the system needs a 100W source, we suggest that users choose a S.P.S. with 130W of output power or more. By doing this, you can effectively boost the reliability of the S.P.S. in your system
B. Choosing functions based on your application:
1. Protection function: Over Voltage Protection (OVP), Over Temperature Protection (OVP), Over Load Protection (OLP), and etc.
2. Application function: Signaling Function (Power Good, Power Fail), Remote Control, Remote Sensing, and etc.
3. Special function: Power Factor Correction (PFC), Uninterruptible Power Supply (UPS) function.

C. Make sure that the model qualifies for the safety standards and EMC regulations you need.
1.Apparent Power=Input Voltage x Input Current (VA) 
2.Real Power= Input Voltage x Input Current x Power Factor (W) From the environment friendly point, the electric power plant needs to generate a power which is higher than apparent power in order to steadily provide electricity to the market. The real usage of electricity should be defined by real power. Assuming the power factor is 0.5, the power plant needs to produce more than 2VA to satisfy 1W real power. On the contrary, if the power factor is 0.95, the power plant only needs to generate more than 1.06VA to provide 1W real power need. It will be more effective.

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